Assume base station sends a signal at T = 0 micro sec. A UE which is at a distance ‘d’ from the base station receives the signal and immediately responds back without any delay. Base station receives the response at T = 1 milli seconds.

How far is the UE from the base station?

This answer was edited.Since the signal travels to UE and then back

The distance from the Base station to UE =

dThe distance from UE to the Base station =

dhence total distance cover by the signal=

2d(since the signal travels from the Base station to UE ad then back)The signal takes

1 milli-secondto travel2dAs we know that 1 milli-second =

1*10^(-3)secand the speed of light =

3*10^8m/swe also know that Velocity of the signal=Distance travelled/ Time taken

hence Distance travelled= Velocity of the signal*Time taken

therefore : 2d=(3*10^8)*(1*10^(-3))

d=150kmThe distance between the UE and the base station can be calculated by using the total time taken for the signal to travel from the base station to the UE and back. As we know that the base station receives the response signal at T = 1 milli seconds (10^-3 seconds) after sending the initial signal.

It will take T/2 time to cover distance ‘d’ .

The distance ‘d’ can be calculated as

d = c * T/2

where d is the distance, c is the speed of light, and T is the total time taken for the signal to travel from the base station to the UE and back.

Substituting the values,

d = (3 x 10^8 m/s) * (10^-3 s)/2 = 1.5 x 10^5 meters

Therefore, the UE is approximately 150,000 meters or 150 km away from the base station.

The distance between UE and base station is 150km .

Since the signal takes

1 milli secondto travel2ddistance (Basestation to UE :‘d’ ,UE to Basestation: distance‘d’),d = 1 milli sec * c/2 where c is speed of light

d = 150km

Since signal takes 2d distance because it travels from base station to ue and vice versa’

So speed =distance/time

speed =3*10^8

time=1ms

d=150km

Total distance = 2d (sent + received)

speed of light = 3 * 10^8

time = 1 milli sec = 1*10^-3

distance = velocity * time

2d = 3*10^8 * 1*10^-3

d= 150km

Distance covered= 2d

Time =1ms

Speed= 3×10^8 m/s

Speed=distance/time

Distance =150km

Distance travelled by the signal ( to and fro)= 2d

Time taken to travel = 1 millisecond

velocity of signal = distance travelled / time taken

As these signals are electromagnetic, they travel with the velocity of light in free space.

Hence taking Velocity = 3*10^8 m/s

2d = 3*10^8*10^(-3)

d = 150 kms.

This answer was edited.The distance between UE and the base station is

d.The distance travelled by the signal from base station to UE and again from UE to base station=d+d=2d.

Velocity=distance/time.

The signal takes

1 milli secondto travel2ddistance.From Base station to UE : ‘d’

From UE to Base station : ‘d’

We know that

Distance = speed *time

2d = 3*10^8*1*10^-3

Speed of light = 3*10^8

d = 150 kmThe distance between UE and Base Station is 150km

answer is uploaded as file

The distance from UE to base station is d.

And the distance from base station to UE is d

Therefore total distance = 2d

We know that distance = speed * time

Time = 1 milli second (given)

Speed = 3 * 10 ^ 8.

2d=3*10 ^8 * 10^(-3)

2d = 300 Kilometers.

d = 150 kilometres.

The signal covers 2 times the distance.

2*Distance = (Speed of EM wave) * 1mSec = 3*10^8m/sec * 10^-3sec = 300Km

So the distance covered = 300/2 = 150Km.

Distance travelled from UE to base station =d

Distance travelled from base station to UE=d

Therefore,

Total distance travelled=2d

We know,

Velocity (v) =Distance travelled(d)/ Time taken(t)————(1)

Speed of light = 3 * 10 ^ 8

Time taken=1 milli second (given)

From eq(1),

2d=v*t

2 d= (3 * 10 ^ 8)* 10^(-3)

d=300/2=150km.